SSC CHSL 2025 PYQ — Question 62

SSC CHSL - 22 Nov 2025 - Shift 2 • Quantitative Aptitude • Q62

A train passes a tunnel 200 m long in 20 seconds. Speed is 72 km/h. Find train's length.

Show answer & explanation

Correct answer: B

Explanation

Given:

Tunnel length = 200 m

Time = 20 s

Speed ​​= 72 km/h

Formula:

Speed ​​= Distance / Time

72 km/h = 72 × 5/18 = 20 m/s

Total distance = Speed ​​× Time = 20 × 20 = 400 m

Length of train = 400 − 200 = 200 m