SSC CHSL 2025 PYQ — Question 74

SSC CHSL - 26 Nov 2025 - Shift 2 • Quantitative Aptitude • Q74

A train leaves A at 6 AM at 60 km/h. Another leaves B at 8 AM at 90 km/h toward A. Distance=540 km. Meeting time?

Show answer & explanation

Correct answer: B

Explanation

Given:

Speed ​​of the first train = 60 km/h

Speed ​​of the second train = 90 km/h

Total distance = 540 km

First train starts = 6 am

Second train starts = 8 am

First train left 2 hours ago

Distance in 2 hours = 60 × 2 = 120 km

Now remaining distance = 540 − 120 = 420 km

Relative speed = 60 + 90 = 150 km/h

Meeting time (after 8 am)

= 420 ÷ 150 = 2.8 hours = 2 hours 48 minutes

Total time = 8:00 + 2:48 = 10:48

The trains will meet at 10:48 am.