SSC CGL 2020 PYQ — Question 74

SSC CGL - 6th March 2020 Shift 3 • Quantitative Aptitude • Q74

A train crosses a platform 180 m long in 60 sec at a speed of 72 km/h. The time taken by the train to cross an electric pole is:

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e 51 sec

Understanding Application

Speed = Distance / time

To convert speed from km/h to m/s

⇒ Speed(km/h) × (5 / 18) = speed(m/s)

First, we will convert speed into m/s

⇒ 72 × (5 / 18)

⇒ 20m/s

Let the speed of the train be 'T'm so the distance covered by the train while covering the platform

⇒ T + 180

By the speed-distance formula

⇒ 20 = (T + 180) / 60

⇒ 1200 = T + 180

⇒ T = 1020 m

For covering the pole train has to cover a distance equal to the length of the train.

⇒ 20 = 1020 / t

⇒ t = 51 Sec