SSC MTS 2022 PYQ — Question 55

SSC MTS - 20 July 2022 - Shift 1 • Quantitative Aptitude • Q55

A toy is formed by placing a solid circular cone on a solid hemisphere and the radius of the common base of the cone and the hemisphere is 15 cm. If the volume of the toy is 2850 π then find the total surface area of that toy.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e.705π cm3

 

If the volume of the toy is 2850 π cm³.

volume of the toy = volume of cone + volume of hemisphere

2850π = 1/3 × π ×  radius 2 × height + 2/3 × π × radius3

2850π = 1/3 × π  × 152 x height +2/3 × π × 153

2850 = 1/3 × 225 × height + 2/3 × 3375

2850 =75 × height + 2 ×1125

2850 = 75 × height + 2250

2850 - 2250 = 75 × height

600 =75 × height

height = 8 cm

total surface area of that toy = lateral surface area of cone + curved surface area

of hemisphere

= π × radius × √(radius2 + height2) + 2 × π × radius2

= π × 15 × √(152 +82) +2 × π × 15²

= π × 15 × √(225 + 64) + 2 × π × 225

= π × 15 × √(289 + 450) × π

= π × 15 ×17 + 450 x π

= 255 ×  π + 450 × π

= 705 π cm²