A thief steals a car at 2:00 p.m. and drives it at 70 km per hour. The theft is discovered at 3:00 p.m. and the owner sets off in another car at 105 km an hour. At what time will the owner overtake the thief?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 5:00 p.m..
Given that, speed of thief = 70 km/h
Speed of owner = 105 km/h
Distance = Speed × Time
When two objects are running in same direction, relative speed is equal to the difference between the individual speeds of the objects.
The thief travelled for one hour before the theft was discovered,
Distance covered by thief in one hour = 70 × 1 = 70 km
Relative speed of thief and owner = 105 - 70 = 35 km/h
Time taken by owner to overtake thief = 70/35 = 2 hours
Hence the owner will overtake thief at 3:00 p.m. + 2 hours = 5:00 p.m..