A thief is spotted by a policeman from a distance of 210 m. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 25 km/h and that of the policeman is 32 km/h, then how far would the thief have run (in m) before he is overtaken?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. 750.
We know that,
Distance = speed × time
Relative speed = (32 - 25) × 5/18 = 35/18 m/s
Time taken to catch the thief = 210 × 18/35 = 108 sec
Distance covered in that time by the thief,
⇒ 25 × 5/18 × 108 = 750 m