A thief escapes custody at 10 a.m. He runs at a speed of 40 km/h. The policeman starts chasing the thief at 11:30 a.m., starting from the point from where the thief escaped custody. The speed of the policeman is 60 km/h. At what time will he catch the thief?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 2:30 p.m.
Given:
A thief escapes custody at 10 a.m.
He runs at a speed of 40 km/h. The policeman starts chasing the thief at 11:30 a.m., starting from the point from where the thief escaped custody.
The speed of the policeman is 60 km/h
Concept used:
When two objects are moving in the same direction, the relative speed = |S1 - S2|
Calculations:
Distance travelled by the thief = 40 × 1.5 = 60 km
Relative speed = 60 - 40 = 20 km/h
Time taken to catch the thief = 60/20 = 3 hour
Therefore, the time at which the police will catch the thief = 11: 30 am + 3 hour = 2 : 30 pm