A sum becomes 8 times of itself in 7 years at the rate of compound interest (interest is compounded annually). In how many years will the sum becomes 4096 times of itself?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 28.
| Understanding/Application |
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Let principal, rate and time be p, r and t respectively. Amount after 7 years = 8p A = p{1 + (r/100)}t |
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ATQ - p{1 + (r/100)}7 = 8p {1 + (r/100)} = 81/7 ....(1 Let Amount after T years be 4096p. p{1 + (r/100)}T = 4096p {1 + (r/100)}T = 4096 Substituting (1 in above equation - (81/7)T = 4096 8T/7 = 84 On comparing - T/7 = 4 T = 28 years |