A starts walking at a speed of 8 km/h. After 8 hours B started travelling on a bicycle at a speed of 24 km/h. The distance from the starting B can catch A is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 96 km.
The speeds of A and B are 8 km/h and 24 km/h respectively.
The distance covered by A = 8 × 8 = 64 km
Relative speed = 24 km/h - 8 km/h = 16 km/h
Time required for B to catch A = 64/16 = 4 hours
The distance from the starting point when B catches A = 4 × 24 = 96 km
Therefore, the distance from the starting B can catch A is 96 km.