A square and a regular hexagon are drawn such that all the vertices of the square and the hexagon are on a circle of radius r cm. The ratio of the area of the square and the hexagon is:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 4 : 3√3
| Application |
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Diagonal of square = 2r cm Area of square = 1/2 × (2r)2 = 2r2 cm2 Area of the triangle AOB = (√3/4)r2 cm2 Area of hexagon = (6√3/4)r2 = (3√3/2)r2 cm2 Required ratio = 2r2 : (3√3/2)r2 = 4 : 3√3 |
