SSC CHSL 2024 PYQ — Question 70

SSC CHSL - 10 July 2024 - Shift 4 • Quantitative Aptitude • Q70

A solid metallic cube having surface area of 54 cm2 is melted to form smaller cubes of surface area 812\frac{8}{12} cm2 each. Find the number of smaller cubes.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 729.

Let the number of smaller cubes be N.

Surface area of cube = 6a2

According to the given question,

Surface area of larger cube, 6A2 = 54

where A is side of larger cube.

⇒ A2 = 9

⇒ A = 3 cm

Now, surface area of smaller cube, 6a2 = 812\frac{8}{12}

where a is side of smaller cube.

⇒ a2 = 1/9

⇒ a = 1/3

Now, N × Volume of smaller cube = Volume of larger cube

⇒ N × (1/3)3 = 33

⇒ N = 27 × 27

⇒ N = 729