A shopkeeper bought 600 oranges and 400 bananas. He found that 30% of oranges and 18% of bananas were rotten. Find the percentage of the fruits in good condition.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 74.8.
Calculations:
Good condition orange = 600 × 70/100 = 420
Good condition bananas = 400 × 82/100 = 328
Total fruits = 600 + 400 = 1000
Required percentage of good condition fruits = ((420 + 328)/1000) × 100
= 748/10 = 74.8%