SSC CHSL 2025 PYQ — Question 52

SSC CHSL - 15 Nov 2025 - Shift 3 • Quantitative Aptitude • Q52

A right prism has a base that is a regular hexagon of side 6 cm. The height of the prism is 10 cm. A square cavity of side 2 cm is carved vertically through the center of the prism from top to bottom. Calculate the volume of the material remaining in the prism.

Show answer & explanation

Correct answer: B

Explanation

Given:

Side of regular hexagon = 6 cm

Height of prism = 10 cm

Side of square cavity = 2 cm

By formula:

Area of ​​regular hexagon = (3√3/2)a²

Area of ​​regular hexagon = (3√3/2) × 6² = 54√3

Volume of prism = base area × height

Volume of prism = 54√3 × 10 = 540√3

Volume of cuboid (cavity) = a²h

Volume of cavity = 2² × 10 = 40

Remaining volume = 540√3 − 40

= 540 × 1.732 − 40 = 895.3 cm³