SSC CGL 2025 PYQ — Question 66

The correct answer is option 3 i.e.  $\sqrt{6}$ : 1.

Let each side of the equilateral triangle = a cm and the regular hexagon = b cm

Area of equilateral triangle $= \frac{\sqrt{3}}{4} a^2$

Area of regular hexagon $= \frac{3\sqrt{3}}{2} b^2$

$\frac{\sqrt{3}}{4} a^2 = \frac{3\sqrt{3}}{2} b^2$

⇒ $\frac{a^2}{4} = \frac{3b^2}{2}$

⇒ a² = 6b²

⇒ a/b = √6/1

⇒ a : b = √6 : 1