A regular hexagonal nut has outer side 6 cm and inner hollow side 3 cm. What is the material approximate area in the cross-section?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 70 cm2.
Area of outer hexagon = (3√3/2) × 62 = (3√3/2) × 36 = 54√3 cm2
Area of inner hexagon = (3√3/2) × 32 = (3√3/2) × 9 = 13.5√3 cm2
Material area = 54√3 – 13.5√3 = 40.5√3 ≈ 40.5 × 1.732 ≈ 70 cm2