A rectangular park is 60 m by 40 m. A semicircular pond of diameter 40 m is inside. What percent of the park's area does the pond occupy?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 26.18%
Area of rectangle = 60 × 40
Area of rectangle = 2400
Radius of semicircle = 40 / 2 = 20
Area of semicircle = (1/2) × π × r²
Area = (1/2) × π × 20²
Area = (1/2) × π × 400
Area = 200π
Percentage = (200π / 2400) × 100
Percentage = (π / 12) × 100
Percentage = (25π / 3)
Percentage = (25 × 22) / (3 × 7)
Percentage = 550 / 21
Percentage = 26.18%