SSC CGL 2024 PYQ — Question 67

SSC CGL - 11 Sep 2024 Shift 2 • Quantitative Aptitude • Q67

A policeman notices a thief from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at 10 km/h and 11 km/h, respectively. What is the distance (in meters) between them after 9 minutes?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. 50.

The thief and the policeman run at the rate of 10 km/h and 11 km/h, respectively

Thief's speed = 10 km/hr = 10 × 1000/60 = 1000/6 = 500/3 m/min

Policeman's speed = 11 km/hr = 11 × 1000/60 = 1100/6 = 550/3 m/min

Thus,

Distance traveled by Thief in 9 minutes = 500/3 × 9 = 1500 meters

Distance traveled by policeman in 9 minutes = 1100/6 × 9 = 1650 meters

Initial distance = 200 meters

Distance covered by policeman in 9 minutes = 1650 - 1500 = 150 meters

Thus,

Total distance between them after 9 minutes = 200 - 150 = 50 meters