A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at speeds of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is:
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 5
Given that
A policeman follows a thief, who is 1250 m ahead of him
The speed of a policeman = 10 km/h
The speed of the thief = 8 km/h
According to the question
⇒The relative speed of Policeman and Thief = 10 - 8 = 2 km/h
⇒Time taken to catch the thief = 1250/2000 = 0.625 hours
Hence, the distance of the thief before being caught by a policeman = 8 × 0.625 = 5 km.