A person was born on 19 April 2008. What day of the week will be on his 22nd birthday?
Show answer & explanation
Correct answer: B
Explanation
Year interval from 2008 to 2029
Total years = 21 years
Count the leap years (after 2008)
2012, 2016, 2020, 2024, 2028 = 5 leap years
Total odd days
Ordinary years = 21 − 5 = 16 → 16 days
Leap years = 5 × 2 = 10 days
Total = 16 + 10 = 26 days
26 / 7 = 5 days
Day of April 19, 2008
April 19, 2008 = Saturday
Move forward by 5 days
Saturday + 5 = Thursday
Thursday + 1 = Friday
Correct Answer = (B) Friday