SSC CHSL 2025 PYQ — Question 74

SSC CHSL - 20 Nov 2025 - Shift 3 • Quantitative Aptitude • Q74

A person walks at 5 km/h. If he increases his speed to 8 km/h, he takes 30 minutes less to cover a distance. What is the distance?

Show answer & explanation

Correct answer: C

Explanation

Given:

First speed = 5 km/h

Second speed = 8 km/h

Time difference = 30 minutes = 1/2 hour

Formula:

Time = Distance / Speed

Let distance = x km

x/5 − x/8 = 1/2

(8x − 5x) / 40 = 1/2

3x / 40 = 1/2

3x = 20

x = 20/3

Distance = 6.67 km