SSC CHSL 2023 PYQ — Question 61

SSC CHSL - 07 Aug 2023 - Shift 3 • Quantitative Aptitude • Q61

In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank. When Mr. Smith went to a restaurant one day, he left his coat near the door. There was (1)________ in the pockets when he left it, so he was very surprised when he took his coat after his meal and found the (2)________ full of jewellery. There was a waiter near the door, so Mr. Smith said to him, “Somebody has made a mistake. He has put some (3)________ in my coat. Take it, and when he comes back, give it to him.” The waiter took it and went away. Suddenly another man came in with a (4)________ just like Mr. Smith’s. “I am sorry,” said the man , “I made a mistake. I took your coat and you have got mine. Please give me my coat and jewellery.” Mr. Smith answered.” I gave the jewellery to the waiter. He will give it to you.” Mr. Smith called the manager of the restaurant; but the manager said, “We have (5)________ waiters here. We have only waitresses.” “You gave the jewellery to a thief!” shouted the other man. “I shall send for the police!” Mr. Smith paid the man a lot of money for the jewellery.

A person invested a certain amount at a rate of 12% simple interest and another amount at a rate of 10% simple interest. He received an annual interest of Rs 130. However, if he had interchanged the amounts invested, he would have received Rs 4 more as interest. How much did he invest at the rate of 12% simple interest originally?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. Rs.500.

Let the amount invested on 12% and 10% rates be x and y respectively.

SI = PRT/100

where P is principal, R is rate and T is time.

According to the given question,

x × 12 × 1/100 + y × 10 × 1/100 = 130

⇒ 12x + 10y = 13000

⇒ 6x + 5y = 6500    ...(i)

Also, y × 12 × 1/100 + x × 10 × 1/100 = 134

⇒ 12y + 10x = 13400

⇒ 5x + 6y = 6700    ...(ii)

Multiplying equation (i) by 6 and equation (ii) by 5,

(i) ⇒ 36x + 30y = 39000   ...(iii)

(ii) ⇒ 25x + 30y = 33500    ...(iv)

Subtracting equation (iv) from equation (iii),

⇒ 11x = 5500

⇒ x = 500