SarkariPYQ

SSC CHSL 2023 PYQ — Question 26

SSC CHSL Tier II - 02 Nov 2023 - Shift 1 • Quantitative Aptitude • Q26

Back to paper

A person covers 14\frac{1}{4} of his journey at the speed of 25 km/h, 12\frac{1}{2} of the journey at 40 km/h and the remaining at the speed of 50 km/h. Find his average speed per hour for the whole journey (in km/h).

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1. i.e.  3641136\frac{4}{11}.

Let the distance be 400 units

Given that

A person covers 14\frac{1}{4} of his journey = 400 × 1/4 = 100 units  with the speed of 25 km/h

He covers 12\frac{1}{2} of the journey = 400 × 1/2 = 200 units at speed of 40 km/h

He covers the remaining distance = 400 - 300 = 100 units at the speed of 50 km/h

Average speed = Total distance/ Total time taken

Total Distance = 400 units

Total time taken = 100/25 + 200/40 + 100/50 = 4 + 5 + 2 = 11 hours

Hence, average speed  = 400/11 =  3641136\frac{4}{11}