A person can hit a target 5 times out of 8 shots. If he fires 10 shots, what is the
probability that he will hit the target twice?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is Option 4 i.e. (1125×38)/(810)
Given that
A person can hit a target 5 times out of 8 shots.
then the probability of hitting a target = 5/8
and the probability of not to hit a target = (8- 5)/8 = 3/8
If he fires 10 shots, then
The probability that he will hit the target twice = 10C2 × (5/8)2 × (3/8)(10 - 2)
= 10C2 × (5/8)2 × (3/8)8
= [10!/(2! × 8!)] × 25 × 38/810
= [(10 × 9)/2] × 25 × 38/810
= 45 × 25 × 38 /810 = (1125×38)/(810)