SSC CHSL 2024 PYQ — Question 55

SSC CHSL - 09 July 2024 - Shift 2 • Quantitative Aptitude • Q55

A part of the journey is covered in 22.5 minutes at a speed of 68 km/h and the remaining part in 12 minutes at a speed of 72 km/h. The total distance of the journey is (to the nearest integer):

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 40 km.

A part of the journey is covered in 22.5 minutes at a speed of 68 km/h

Time:

⇒ 22.5 minutes = 22.5/60 = 0.375 hours

⇒ 12 minutes = 12/60 = 0.2 hours

Now,

Distance = Speed × Time

Distance for the first part = 68 × 0.375 = 25.5 km

Distance for the second part = 72 × 0.2 = 14.4 km

Total distance = 25.5 + 14.4 = 39.9 km or 40 km approximately