SSC CGL 2026 PYQ — Question 12

SSC CGL Tier II - 19 Jan 2026 - Shift 1 • Quantitative Aptitude • Q12

A number is chosen at random from the set (1, 2, 3, 120). What is the probability that the number chosen is divisible by 6 or 8 but not divisible by 24?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 25120{25\over120 }.

Numbers from 1 to 120:

Number divisible by 6 = 120/6 = 20

Number divisible by 8 = 120/8 = 15

Number divisible by 24 (LCM of 6 and 8) = 120/24 = 5

Divisible by 6 or 8 = 20 + 15 – 5 = 30

Numbers divisible by 6 or 8 but not 24 = 30 – 5 = 25

Total numbers = 120

Probability = 25/120