A mixture containing 72% oil is mixed with another mixture containing 48% oil in the ratio 6 : 16. What is the percentage of oil in the mixture formed?
Show answer & explanation
Correct answer: C
Explanation
Given:
Oil in the first mixture = 72%
Oil in the second mixture = 48%
Ratio of mixture = 6 : 16
Formula:
Percentage of mixture = (a × p + b × q) / (a + b)
= (6 × 72 + 16 × 48) / (6 + 16)
= (432 + 768) / 22
= 1200 / 22
= 54.54% (approximately)