A metallic wire is melted and recast into a circular ring of radius 28 cm. If the volume of the wire was 1232 and its thickness is 2 cm, what is the width of the ring?
Show answer & explanation
Correct answer: C
Explanation
Volume = 1232 cm³
Radius (R) = 28 cm
Thickness = 2 cm
Volume = 2πR × Width × Thickness
1232 = 2 × (22/7) × 28 × Width × 2
1232 = 352 × Width
Width = 1232 / 352 = 3.5 cm