SSC CGL 2025 PYQ — Question 66

The correct answer is Option 4 i.e.  $120 ( \sqrt{3} +1)$ m.

Angle of depression to first car = 30° ⇒ Angle of elevation from car to top = 30°

Angle of depression to second car = 45° ⇒ Angle of elevation to top = 45°

Let distance of first car from tower = d₁

$\tan 30^\circ = \frac{120}{d_1}$

⇒ $d_1 = \frac{120}{\tan 30^\circ} = \frac{120}{1/\sqrt{3}} = 120\sqrt{3}$ m

Let distance of second car from tower = d₂

$\tan 45^\circ = \frac{120}{d_2}$

⇒ $d_2 = \frac{120}{1} = 120$ m

Distance between cars = d₁ + d₂ $=120\sqrt{3} + 120 = 120(\sqrt{3} + 1)$ m