SSC CGL 2025 PYQ — Question 72

SSC CGL - 23 Sep 2025 - Shift 2 • Quantitative Aptitude • Q72

A man reduces his speed from 20 kmph to 18 kmph. So, he takes 8 minutes more than the normal time. What is the distance traveled by him?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 24 km.

Let normal time = t hours

18(t + 8/60) = 20t

⇒ 18t + 144/60 = 20t

⇒ 2t = 144/60 = 12/5

⇒ t = 6/5 hours

Distance = 20 × 6/5 = 24 km