SSC MTS 2019 PYQ — Question 73

SSC MTS Previous Year - 02 August 2019 - Shift 1 • Quantitative Aptitude • Q73

A man leaves from P at 6 am and reaches Q at 2 pm on the same day. Another man leaves Q at 8 am and reaches at 3 pm on the same day. At what time do they meet?
 

Show answer & explanation

Correct answer: C

Explanation

Correct Answer is option 3 i.e. 10:48 am

Understanding

Application

From the question:

P takes 8 hours and Q takes 7 hours.

Suppose total distance = a

⇒ Speed of P = a/8

Speed of Q = a/7

And

Relative speed = a/8 + a/7 = 15a/56

 

Now,

Distance covered by P till 8 am (When Q starts the journey) = 2a/8 = a/4

Then,

Remaining distance = a – a/4 = 3a/4

Time after 8 pm when they will meet = (3a/4)/(15a/56)

= 14/5 hours

= 2 hours 48 minutes

Hence, time = 10:48 am