SSC CGL 2025 PYQ — Question 52

SSC CGL - 26 Sep 2025 - Shift 1 • Reasoning • Q52

A man is 4 times as old as his daughter. In 20 years, he will be twice as old as she will be then. How old is the daughter now?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 10.

Let daughter’s present age = x

Man’s present age = 4x

After 20 years:

Daughter’s age = x + 20

Man’s age = 4x + 20

Daughter’s present age = 4x + 20 = 2(x + 20)

4x + 20 = 2x + 40

2x = 20

x = 10