A man can finish a piece of work in 15 days. A woman can complete the same work in 10 days. Both work together for 5 days, then the man leaves. How many days will be taken by the woman to finish the remaining work?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 5/3
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Understanding |
Application |
Calculation |
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A man and A woman can complete the work in 15 and 10 days respectively. |
Suppose, Total work = LCM of 15 and 10 = 30 units |
LCM of 15 and 10 = 5 × 2 × 3 = 30 |
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Efficiency = Work/Time |
Efficiency of a man = 2 |
⇒ 30/15 = 2 |
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Efficiency = Work/Time |
Efficiency of a man = 3 |
⇒ 30/10 = 3 |
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They worked for 5 days together. |
So, Work done = 25 units Remaining work = 30 – 25 = 5 units |
⇒ 5 × (2 + 3) = 25 |
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Remaining work is done by the woman |
Time taken by woman = 5/3 |
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