SSC CGL 2025 PYQ — Question 57

The correct answer is option 1  i.e. -3.

Two points A(2, 5) and B(8, -1)

Here, x₁ = 2, y₁ = 5 and x₂ = 8, y₂ = - 1

Midpoint of AB $=\left(\frac{x_1+x_2}{2} \right), \left(\frac{y_1+y_2}{2} \right)=\left(\frac{2+8}{2} \right), \left(\frac{5+(-1)}{2} \right)=\left({10\over2},{4\over2} \right)=(5,2)$

Slope of AB $=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-5}{8-2}=\frac{-6}{6}=-1$

Perpendicular slope (m) = (-1)/(-1) = 1

Equation of perpendicular bisector through M: (y - y₁) = m(x - x₁)

⇒ y – 2 = 1(x – 5)

⇒ y = x – 3

For y-intercept, put x = 0: y = –3