SSC CPO 2025 PYQ — Question 59

SSC CPO - 12 Dec 2025 - Shift 2 • Quantitative Aptitude • Q59

A jeep covers a distance of 180 km at a certain speed. If the speed is increased by 15 km/h, it takes 1 hour less.
Find the original speed.

Show answer & explanation

Correct answer: A

Explanation

Distance = 180 km

Difference in time = 1 hour

Let the original speed be = x

Time = 180/x

New speed = x + 15

New time = 180/(x + 15)

180/x − 180/(x + 15) = 1

[180(x + 15) − 180x] / [x(x + 15)] = 1

180x + 2700 − 180x = x(x + 15)

2700 = x² + 15x

x² + 15x − 2700 = 0

(x + 60)(x − 45) = 0

x = 45 km/h