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SSC GD 2024 PYQ — Question 58

SSC GD Const (English) - 26 Feb 2024 - Shift 4 • Quantitative Aptitude • Q58

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A is thrice as fast as B and B is twice as fast as C. If the journey is covered by C in 66 minutes, then find the time taken by A.

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 11 minutes.

The speed of C =  vC. 

the speed of B is:

vB = 2vC  (since B is twice as fast as C)

And the speed of A is:

⇒ vA=3vB=3(2vC)=6vCv_A = 3v_B = 3(2v_C) = 6v_C (since A is thrice as fast as B)

Time ∝\propto  (1) / (Speed)

 

Time taken by A = 1 / 6 × 66 = 11  minutes