A is 40% more than B and B is 60% less than C. If C is 60% more than D then which of the following is true?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. B is 36% less than D
| Application |
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Let D = 100x C is 60% more than D So, C = 100x + (100x × 60)/100 = 160x B is 60% less than C So, B = 160x - (160x × 60)/100 = 64x A is 40% more than B So, A = 64x - (64x × 40)/100 = 89.6x Now consider option A : C is 60% more than B. Difference between B and C = 160x – 64x = 96x Percentage by which C is more than B =(96x/64x) 100 = 150% So option A is wrong. Now consider option B: B is 36% less than D Difference between B and D= 100x – 64x = 36x Percentage by which B is less than D = (36x/100) × 100 = 36 Which is a correct statement. |