A hemispherical bowl is made of 1 cm thick copper.. The inner radius of the bowl is 6 cm. Find the cost to paint the outer curved surface area of the bowl, if the paint cost is ₹2 per cm²? (Use π = )
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. Rs.616.
Outer radius = Inner radius + thickness = 6 + 1 = 7 cm
Outer curved surface area (CSA) of hemisphere = 2 × π × r2 = 2 × × 7 × 7 = 2 × 22 × 7 = 308 cm²
Cost = Area × Rate = 308 × 2 = ₹616