A hemispherical bowl has 3.5 cm radius. It is to be painted inside as well as outside. Find the cost of painting it at the rate of ₹15 per 10 cm2. (Use π = 22/7.)
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. ₹231.
Area to be painted (inside + outside of hemisphere) = 4πr2
= 4 × 22/7 × 3.5 × 3.5
= 154 cm2
Cost = 154 × 15/10 = ₹231