A girl, walking at 5/6 of her usual speed, misses the bus by 7 minutes. How long does she usually take to reach the bus stop?
Show answer & explanation
Correct answer: B
Explanation
the correct answer is option 2 i.e. 35 minutes.
Let's assume the usual speed of a girl is '6y'.
By the speed of 6y, she covers 'd' distance is 't' time.
d= 6yt Eq .(i)
A girl, walking at 5/6 of her usual speed, misses the bus by 7 minutes.
d = 6y × 5/6(t + 7) Eq .(ii)
Eq.(I) = Eq. (ii)
So
⇒ 6yt = 6y × 5/6 × (t + 7)
⇒ t = 5/6 × (t + 7)
⇒ 6t = 5(t + 7)
⇒ 6t = 5t + 35
⇒ 6t - 5t = 35
t = 35 minutes