A fruit seller sells 45% of the oranges that he has along with one more orange to a customer. He then sells 20% of the remaining oranges and 2 more oranges to a second customer. He then sells 90% of the now remaining oranges to a third customer and is still left with 5 oranges. How many oranges did the fruit seller have initially?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 120
Let the initial oranges with the fruit seller be x.
1st selling = 0.45x + 1
Remaining = x - (0.45x+1)=0.55x - 1
2nd selling = (1/5) × (0.55x - 1) = 0.11x - 0.2 + 2 = 0.11x + 1.8
Remaining after second selling = 0.55x - 1 - (0.11x + 1.8) = 0.55 x - 0.11x - 1 - 1.8 = 0.44x - 2.8
3rd selling 90% × (0.44x - 2.8)
Remaining after 3rd selling = 0.1 × (0.44x - 2.8) = 0.044x - 0.28
According to the question-
0.044x - 0.28 = 5
⇒ 0.044x = 5.28
⇒ x = (5.28/0.044) = 120