SSC MTS 2024 PYQ — Question 3

SSC MTS - 08/10/2024 - (9:00 AM - 11:00 AM) • Quantitative Aptitude • Q3

A fast train takes 1 hour less than a slow train for a journey of 96 km. If the speed of the slow train is 8 km/h less than that of the fast train, then find the speeds of the fast train and slow train, respectively.

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 32 km/h, 24 km/h.

Let the speed of a fast train = x km/hr

Then slow train = (x - 8) km/hr

According to the question,

⇒ 96(x−8)−96x=1{{96\over(x-8)}-{96\over x}}={1}

⇒ 96x - 96(x - 8) = x(x - 8)

⇒ 96x - 96x + 768 = x2 - 8x

⇒ x2 - 8x - 768 = 0

⇒ x2 - 32x + 24x - 768 = 0

⇒ x(x - 32) + 24(x - 32) = 0

⇒ (x + 24)(x - 32) = 0

⇒ x = 32

Fast = 32 km/h, Slow = 24 km/h