SSC GD 2023 PYQ — Question 57

The correct answer is Option 3 i.e. 25 : 24.

Let x = velocity of dog and, y = velocity of hare

t₁ = time taken by the dog to take one leap and, t₂ = time taken by the hare to take one leap

Time taken by the dog to take 5 leaps is equal to time taken by hare to take 6 leaps

So,

⇒ 5t₁ = 6t₂

⇒ t₁/t₂ = 6/5.....(1)

4 leaps of the dog are equal to 5 leaps of the hare

So, equating the distance covered

⇒ 4 × x × t₁ = 5 × y × t₂

⇒ x/y = 5/4 × t₂/t₁

⇒ x/y = 5/4 × 5/6

⇒ x/y = 25/24

⇒ x : y = 25 : 24