A die is thrown 1,000 times with the frequencies for the outcomes 1, 2, 3, 4, 5 and 6 as given in the following table. How many times is the number appearing on the die greater than or equal to 5?
| Outcome | 1 | 2 | 3 | 4 | 5 | 6 |
| Frequency | 179 | 150 | 157 | 149 | 175 | 190 |
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 365
Explanation:
According to the given table,
The number appearing on the die greater than or equal to 5 = 175 + 190 = 365.
Hence the required answer is 365.