SSC CHSL 2025 PYQ — Question 64

SSC CHSL - 19 Nov 2025 - Shift 1 • Quantitative Aptitude • Q64

A cyclist rides at a speed of 30 km/h and covers a distance of 90 km. Then, he increases his speed by 20% and covers another 60 km. What is the total time taken for the journey?

Show answer & explanation

Correct answer: A

Explanation

Given:

Initial speed = 30 km/h

First distance = 90 km

Speed ​​increase = 20%

Second distance = 60 km

Formula:

Time = Distance / Speed

First part time = 90 / 30 = 3 hours

New speed = 30 × 1.20 = 36 km/h

Second part time = 60 / 36 = 5/3 hours = 1 hour 40 minutes

Total time = 3 hours + 1 hour 40 minutes = 4 hours 40 minutes