SSC CHSL 2024 PYQ — Question 72

SSC CHSL - 10 July 2024 - Shift 3 • Quantitative Aptitude • Q72

A cuboid with dimensions 20 cm, 12 cm, and 10 cm is cut into 8 identical pieces by 3 cuts. What will be the total surface area of all the pieces?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 2240 cm2.

Surface area of each small piece = 2(L/2 × B/2 + B/2 × H/2 + H/2 × L/2)

According to the given question,

Surface area of smaller cuboid = 2(10 × 6 + 6 × 5 + 5 × 10)

⇒ 2(60 + 30 + 50)

⇒ 2 × 140 = 280 cm2

Total surface area of smaller cuboid = 8 × 280 = 2240 cm2