A container holds a mixture of three liquids A, B, and C in the ratio 3 : 2 : 4. If 9 liters of liquid A, 12 liters of liquid B, and a certain quantity of liquid C are added to the container, the new ratio of liquids A, B, and C becomes 9 : 8 : 15. Find the quantity (in liters) of liquid C that was added.
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Correct answer: C
Explanation
The correct answer is option 3 i.e. 21 liters.
Let the initial quantities of A, B and C be 3x, 2x and 4x respectively.
Let the amount of R added be k.
Final amounts of A, B and C are as follows:
A = 3x + 9; B = 2x + 12 and C = 4x + k
For A nd B,
⇒ 24x + 72 = 18x + 108
⇒ 6x = 36
⇒ x = 6
For A and C,
⇒ 15x + 45 = 12x + 3k
⇒ 3k = 45 + 3(6)
⇒ 3k = 63
⇒ k = 21