A container holds 70 litres of a milk water mixture in which water makes up 10% of the total. How many litres of pure water should be added so that the proportion of water in the mixture increases to 25%?
Show answer & explanation
Correct answer: D
Explanation
Given:
Total mixture = 70 liters
Water = 10%
Initial water = 10% × 70 = 7 liters
Let x liters of water be added.
New water = 7 + x
New total mixture = 70 + x
As per the question:
(7 + x) / (70 + x) = 25 / 100
(7 + x) / (70 + x) = 1 / 4
4(7 + x) = 70 + x
28 + 4x = 70 + x
3x = 42
x = 14 liters