SSC MTS 2026 PYQ — Question 54

SSC MTS - 19 Feb 2026 - Shift 2 • English • Q54

A constant force acts on an object of mass 6 kg for a duration of 5 seconds. It increases the object's velocity from 3 m/s to 8 m/s. Find the magnitude of the applied force.

Show answer & explanation

Correct answer: A

Explanation

Correct Answer:

Option 1: 6 N

 

Explanation:

To solve this problem, Newton's Second Law is applied:

Force = Mass × Acceleration

 

Change in velocity = 8 – 3 = 5 m/s

Time = 5 seconds

 

Acceleration = 5 / 5 = 1 m/s²

 

Now,

Force = 6 × 1 = 6 N

 

Therefore, the applied force is 6 Newtons.

 

Potential Questions for Upcoming Exams:

Question: What is the SI unit of force?

Answer: Newton

Question: How many laws of Newton are there?

Answer: 3

Question: What is acceleration?

Answer: The rate of change of velocity

Question: What is mass?

Answer: The quantity of matter