A conical bucket is cut at one-third its height from the top. What is the ratio of the volumes of the two parts (top part to bottom part)?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 1 : 26.
Let original cone height = H
Top part height = H/3
Bottom part height = H - H/3 = 2H/3
Small cone (top) volume/Original cone volume = (H/3 ÷ H)3 = (1/3)3 = 1/27
If original cone volume = 27 then bottom part volume = 1 - 27 = 26
Required ratio = 1 : 26