SSC MTS 2026 PYQ — Question 36

SSC MTS - 18 Feb 2026 - Shift 2 • Reasoning • Q36

A clock is 2 minutes slow at 1:15 PM and 6 minutes fast at 7:15 PM. At what time (in PM) will it show the correct time?

Show answer & explanation

Correct answer: C

Explanation

Total Time Difference:

The clock went from being 2 minutes behind to 6 minutes ahead; this means it gained a total of 2 + 6 = 8 minutes.

Rate of Gain:

The clock gained 8 minutes over a period of 6 hours. Therefore, the time required to gain 1 minute is: 6 hours / 8 = 3/4 hours.

When will it show the correct time?

The clock will show the correct time once it has made up for its initial 2-minute delay.

Time required to gain 2 minutes = 2 × (3/4 hours) = 1.5 hours (i.e., 1 hour and 30 minutes).

Calculating the Exact Time:

Adding 1 hour and 30 minutes to the starting time (1:15 PM): 1:15 PM + 1:30 = 2:45 PM.

The clock will show the correct time at 2:45 PM.

The correct option is: C) 2:45